1260=x^2-x

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Solution for 1260=x^2-x equation:



1260=x^2-x
We move all terms to the left:
1260-(x^2-x)=0
We get rid of parentheses
-x^2+x+1260=0
We add all the numbers together, and all the variables
-1x^2+x+1260=0
a = -1; b = 1; c = +1260;
Δ = b2-4ac
Δ = 12-4·(-1)·1260
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5041}=71$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-71}{2*-1}=\frac{-72}{-2} =+36 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+71}{2*-1}=\frac{70}{-2} =-35 $

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